1=-(1.59*10^-3)*x+1.55

Solution for 1=-(1.59*10^-3)*x+1.55 equation:

1=-(1.59*10^-3)*x+1.55

We move all terms to the left:

1-(-(1.59*10^-3)*x+1.55)=0


We calculate terms in parentheses: -(-(1.59*10^-3)*x+1.55), so:

-(1.59*10^-3)*x+1.55

We multiply parentheses

-15.9x^2+3x+1.55

Back to the equation:

-(-15.9x^2+3x+1.55)


We get rid of parentheses

15.9x^2-3x-1.55+1=0

We add all the numbers together, and all the variables

15.9x^2-3x-0.55=0

a = 15.9; b = -3; c = -0.55;
Δ = b2-4ac
Δ = -32-4·15.9·(-0.55)
Δ = 43.98
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{43.98}}{2*15.9}=\frac{3-\sqrt{43.98}}{31.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{43.98}}{2*15.9}=\frac{3+\sqrt{43.98}}{31.8}
$